Special Function Forms

Not all functions are given by one simple formula. These five special forms appear everywhere in analysis and applications.

Composite Functions

Composite function

If u=g(x)u = g(x) and y=f(u)y = f(u), then y=f(g(x))y = f(g(x)) is the composite of ff and gg.
Domain: all xx such that xD(g)x \in D(g) and g(x)D(f)g(x) \in D(f).

Example: f(u)=euf(u) = e^u, g(x)=x2+1g(x) = x^2 + 1f(g(x))=ex2+1f(g(x)) = e^{x^2+1}.

Inverse Functions

Inverse function

If ff is one-to-one on DD, the inverse f1f^{-1} satisfies f(f1(y))=yf(f^{-1}(y)) = y and f1(f(x))=xf^{-1}(f(x)) = x.

  • Graphs of ff and f1f^{-1} are symmetric about y=xy = x.
  • Monotonicity is preserved: if ff is strictly increasing, so is f1f^{-1}.

Piecewise Functions

  • Different expressions on different intervals.
  • Pay attention to continuity at the breakpoints.
  • Example: absolute value f(x)={x,x0x,x<0f(x) = \begin{cases} x, & x \ge 0 \\ -x, & x < 0 \end{cases}.

Implicit Functions

  • Relation given by F(x,y)=0F(x, y) = 0 instead of y=f(x)y = f(x) explicitly.
  • Under mild conditions, the implicit function theorem guarantees a local function y=φ(x)y = \varphi(x).
  • Example: circle x2+y21=0x^2 + y^2 - 1 = 0y=±1x2y = \pm\sqrt{1 - x^2}.

Parametric Functions

  • Both variables expressed via a parameter tt: (x(t),y(t))(x(t), y(t)).
  • Great for curves that are hard to describe explicitly (cycloids, Lissajous curves).
  • Tangent slope: dydx=y(t)x(t)\dfrac{dy}{dx} = \dfrac{y'(t)}{x'(t)} when x(t)0x'(t) \neq 0.

练习题

练习 1

Given f(x)=2x+3f(x) = \sqrt{2x+3} and g(x)=x21g(x) = x^2 - 1, write f(g(x))f(g(x)) and find its domain.

参考答案

f(g(x))=2(x21)+3=2x2+1f(g(x)) = \sqrt{2(x^2 - 1) + 3} = \sqrt{2x^2 + 1}.
Need 2x2+102x^2 + 1 \ge 0, always true ⇒ domain R\mathbb{R}.

练习 2

Find the inverse of y=e2x+1y = e^{2x} + 1 and its domain.

参考答案

y1=e2xln(y1)=2xx=12ln(y1)y - 1 = e^{2x} \Rightarrow \ln(y-1) = 2x \Rightarrow x = \tfrac{1}{2}\ln(y-1).
Swap x,yx, y: y=12ln(x1)y = \tfrac{1}{2}\ln(x-1) with domain (1,+)(1, +\infty).

练习 3

For the parametric curve x=costx = \cos t, y=sinty = \sin t, compute dydx\dfrac{dy}{dx}.

参考答案

x(t)=sintx'(t) = -\sin t, y(t)=costy'(t) = \cos tdydx=costsint=cott\dfrac{dy}{dx} = \dfrac{\cos t}{-\sin t} = -\cot t (when sint0\sin t \neq 0).


总结

本文出现的符号

符号类型读音/说明在本文中的含义
f(g(x))f(g(x))数学符号f of g of x复合函数
f1(x)f^{-1}(x)数学符号f inverse of x反函数
F(x,y)=0F(x, y)=0数学符号F of x y equals zero隐函数关系
(x(t),y(t))(x(t), y(t))数学符号x of t, y of t参数方程
dydx\dfrac{dy}{dx}数学符号dy over dx斜率或导数
R\mathbb{R}数学符号Real numbers全体实数集合

中英对照

中文术语英文术语音标说明
复合函数composite function/kəmˈpɒzɪt ˈfʌŋkʃən/通过嵌套得到的新函数
反函数inverse function/ɪnˈvɜːs ˈfʌŋkʃən/将输出映回输入的函数
分段函数piecewise function/ˈpiːswaɪz ˈfʌŋkʃən/不同区间使用不同表达式
隐函数implicit function/ɪmˈplɪsɪt ˈfʌŋkʃən/由方程关系确定的函数
参数方程parametric equation/ˌpærəˈmɛtrɪk ɪˈkweɪʒən/用参数描述曲线的方程
周期参数parameter/pəˈræmɪtər/描述曲线位置的变量

Chapters